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If
`log_(4)2 + log_(4)4 + log_(4)x + log_(4)16 = 6`
then
`x =`
64
4
8
32
can i get the solution
Answer
about 10 years ago
Suman
Answers
0
32
almost 5 years ago
Dhareppa
0
By using simple properties of logarithms this problem can easily done
about 7 years ago
9490555945
0
32
about 7 years ago
Siril
0
2*4*x*16=4*4*4*4*4*4
about 7 years ago
Sai charan
0
32
about 7 years ago
Chanchal p...
0
32
almost 8 years ago
Ritika
0
it can be written as log(2*4*x*16)/log4=6 log(128x)=6log4 128x=4*4*4*4*4*4 x=32
almost 8 years ago
Rishi raj ...
0
log2= 1/2, log4= 1, log16= 2 1/2+1+2+logx= 6 logx= 5/2 4^5/2=x=32
about 8 years ago
Sukanya
0
x = 32
about 9 years ago
Amey avani...
0
64
about 9 years ago
Pushpa
Doubts in this Question
1
how is it 32 what nonsense
about 7 years -
Joanna
0
how to do it
about 9 years -
Vishal
0
what is the log of 2
about 9 years -
Sonia samuel
0
how
about 10 years -
Priyanka kumari
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Can I get the working for this question?????
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