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If
`log_(4)2 + log_(4)4 + log_(4)x + log_(4)16 = 6`
then
`x =`
64
4
8
32
how is it 32 what nonsense
Answer
about 7 years ago
Joanna
Answers
0
(1/2) + 1 + log4^x +2 =6 log4^x = 6 - (7/2) log4^x = (5/2) 4^{5/2) = x X = 2^5 X = 32 . That's it .
almost 7 years ago
9490555945
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