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So basically here it is to find E0 of cell which is E cathode- E anode
hence here it is 0.40-0.76=0.36
about 5 years ago
Dhanush
Both OXIDATION POTENTIALS are given. (PLZ OBSERVE)
Zn has higer OP so it will be the anode
Fe therefore is cathode.
Fe will have red pot. of -0.40 (OBVIO)
E0CELL = E0RED+E0oxi
almost 8 years ago
Arpan mukh...
they asked Eo for the overall reaction
since Eo value of zinc is higher, it will undergo reduction (cathode)
therefore Eo of cell =Ecathode -Eanode(this is how i remember it)
therefore Eo of cell = 0.76-0.40= 0.36 V
almost 8 years ago
Vaisakh
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In the given both are oxidising potentials. We'
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