E0 for a cell having, Fe `->` Fe2+ + 2e; E0 = 0.40V Zn ` ->` Zn2+ + 2e; E0 = 0.76 V
0.36 V
-0.36 V
-1.16 V
1.16 V
In the given both are oxidising potentials. We're supposed to convert them to reduction potentials and then apply E(more negative)- E(less negative).