Two resistances 6 and 4 are connected in parallel and the combination is connected in series with a resistance of 2.6 and an accumulator of emf 2 V. Then the current in the circuit is
can anyone explain how to solve this sum?????
1/r1+1/r2=?
1/6+1/4=?( find out the answer..) take its reciprocal keep it as Rp then,
calculate rp+rs ( Rs is 2.6, so Rp+2.6).. take that answer a R.. then,
V=2v(given)
use formula i=v/r
solve..