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x^2/25+y^2/9= 1 is a mojor axis ellipse
foci = ( +or- ae , 0 ) ; here a^2 = 25 , so a = 5
e = root of ( 1 - ( b^2 / a^2 ) ) , so e = 4/5 hence ae = 4 nd foci = (+-4,0)
over 10 years ago
Priya
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