HBr when reacts alone(with alkene) then it follows Markonikov's rule (while breaking double bond) i.e. Br will get attached to the most stable C atom(by breaking the double bond). But here since peroxide is present it will follow Anti Markonikov's rule and Br will not get attached to stable location. If Propene could had reacted with HBr only, it will form 2-Bromopropane. And if it is reacted in presence of peroxide it will form N Propyl bromide (or 1-Bromopropane)

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I Think the answer is 3. As peroxides are present reactionfollows anti markonikovs rule

the correct answer is N propyl bromide since it follows AMK rule in presence of peroxide

y you are correct but the (N) must be small (n) ,,,,,,, since there meanings are diffrent

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