Answers
velocity is root of 2gh and momentum,p=mv
mv/v=m as mv=p and v=root of 2gh
Therefore,m=P/root of 2gh
about 8 years ago
Anjana c j
We know
p=m×v
Also, v=√2gh
Then compare both,
So,mv=m√2gh=p
Therefore,
m=p/√2gh
about 8 years ago
Darsana s
let,
mass=m;
H max=h;
V initial=u;
V final= v=0;
T total =2t (where t is time in assending)
now,
as v^2 -u^2 =2(-g)h
0 -u^2=-2gh
u=(2gh)^(1/2)
since,
p=mv //where p is momentum
m=p/v
m=p/{(2gh)^(1/2)} =>answer
about 8 years ago
Aditya
momentum divided by velocity = mass; in formula wise momentum = p and velocity = square root of 2gh.... so the mass of the body = p/square root of 2gh......................... so first option my friend
about 8 years ago
Vamsi
we have m=p/v..
when a body is dropped,v=sqrt(2gh)...
equating on m, we get m=p/sqrt(2gh).
about 9 years ago
Jubi Cyria...
Wkt p^2/2m= energy...hence mgh=p^2/2m..solving for m we get the req ans
about 9 years ago
Prithviraj
P=mv than m=p/v than find than value of v and put the value of v
almost 10 years ago
Uditshanka...
it is from projecting a body upward... from intermediate firstyear textbook
about 10 years ago
Shabinataj
p=mv
the body is dropped from height h= v=square root of 2gh
m=p/v = m=p/square root of 2gh
over 10 years ago
Anvesh
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