If there is a positive error of the 50% in the measurement of velocity of a body. Then the error in the measurement of kinetic energy is
25%
50%
100%
125%
K.E. = 0.5mv^2 dk = 0.5m*2v*dv k.e is propr. to square of v error in K.E = 0.5^2v = 0.25K therfore, = k + 0.25k = 1.25k = 125%