Answers
IN A SHORTCUT METHOD:- take the most common probable, expected number, and then put this value between them, hence, for the above question, u get 60, as 20 is a very low number and 120 is not common
about 10 years ago
Abhinav
P(AUB)=P(A)+P(B)-P(A/B)
200=140+120-P(A/B)
200=260-P(A/B)
P(A/B)=260-200
P(A/B)=60
about 10 years ago
Abhishek
Doubts in this Question
0
what is the procedure to do this sum and formul
over 4 years - Guru aravind
0
caliculation
about 10 years - Haswanth
0
how to solve?
about 10 years - Lokitha
0
i considered p(a) as one event and p(b) as anot
about 10 years - Karri Jayesh
2
what is the formula to find n(AUB)
over 10 years - Vishwajeet
