In both the matrix, alpha and beta, apply R1 => R1-R2 and R2 => R2-R3. Then take (x-y) and (y-z) common from R1 and R2 from both the matrix. Then expand the matrix by C1. The answer will be Option 2.
Multiple the first row with x , second with and third with z....take out xyz in common and it gets cut with the xyz outside. now you exchange the columns two times (-)(-) thats why we get positive and the R.H.S. HENCE ALPHA=BETA