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how to solve this problem

over 11 years ago
Abhilasha
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In both the matrix, alpha and beta, apply R1 => R1-R2 and R2 => R2-R3. Then take (x-y) and (y-z) common from R1 and R2 from both the matrix. Then expand the matrix by C1. The answer will be Option 2.
about 11 years ago
Kartheeswa...
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Multiple the first row with x , second with and third with z....take out xyz in common and it gets cut with the xyz outside. now you exchange the columns two times (-)(-) thats why we get positive and the R.H.S. HENCE ALPHA=BETA
about 11 years ago
Aanchal Bu...
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