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i want 12th question

over 11 years ago
Sanjay
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Answers

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3
almost 8 years ago
Jishnu
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3
about 9 years ago
Tawfeeq
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AUB MEANS ALL AREA UNDER A AND B ..AND COMPLEMENT ALL THE AREA IN UNIVERSAL SET OUT OF A AND B ...NOW SINCE (AUB)' IS AREA OUT OF A AND B SO THERE NOTHING COMMON BETWEEN (AUB)' AND A HENCE...(AUB)'intersectiona= phi
about 9 years ago
Ashish
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it is null set.use venn diagrams
about 10 years ago
Lohith
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4
about 10 years ago
Amit
Tiny_avatar6

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option 4 draw venn diagram its easy
about 10 years ago
Prem
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let us take the values of a and b and solve it
over 10 years ago
K ramsunde...
Tiny_avatar15

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consider A ={1234} B ={2345} then A^[AUB] is A union B consists of all elements of A and B and its complement is some set of elements like {6789} this set and A set complement is automatically 0 elements ie pie always use examples in sets
over 10 years ago
Aditya Adi...
Tiny_avatar1

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Let U stand for union and | stand for intersection and Pi stands for the null set as i cannot write the usual symbols.Solution is as follows: A | (A U B)' = A | (A' | B') = (A | A') | B' = Pi | B' = Pi Explanation: Apply the usual formula for the compliment and the next as intersection holds associative law calculate the intersection of A and A' which is a null set and hence the answer follows.
over 10 years ago
Yama
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4.
over 10 years ago
Shivam
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by using de-morgan's law and distributive law we will get null set
about 11 years ago
Sireesha k...
Tiny_avatar10

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take the example first always A- (1,2,3,4) and B-(3,4,5,6) A U B - (1,2,3,4,5,6) (A U B)' - FIE
about 11 years ago
Rahul
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the answer is 4 try solving it by representing them in the set form
over 11 years ago
Tarun
Tiny_avatar19

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using venn diagram we can prove it answer is 4
over 11 years ago
Aisha
Tiny_avatar5

Doubts in this Question

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i want 12th question
over 11 years - Sanjay
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i want 12th question
over 11 years - Sanjay

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