60 g of a compound on analysis gave 24 g of C, 4 g of H and 32 G of O. The empirical formula of the compound is
C2H4O2
CH2O2
C2H2O2
CH2O
There are two correct answers to this question: 'a' and 'd'. I selected 'a', it's been given wrong. In the solution, the answer is 'a' or 'd'.