Let `delta`(t) denote the delta function. The value of the integral `int_-oo^oodelta(t)cos((3t)/2)dt` is
1
-1
0
`pi/2`
delta(t) = 1 only on t = 0 and at that time cos(0) = 1 (agreed).
But integration of cos(t) = sin(t) where sin(0) = 0. hence, the answer should be 0. why 1?