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Answersi cant see the solution of this problem
almost 10 years ago
Prajwal k ...
Answers
range= (u^2sin^2alpha)/2g(alpha is the angle of projection)
range1=range2 and also their initial velocities are equal
=> sin^2alpha1=sin^2alpha2
=>sin(alpha1)=sin(alpha2)
but time of flight i.e t=2usin(alpha)/g
=>t1/t2= sin(alpha1)/sin(alpha2)= 1
almost 10 years ago
Shwetha
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